Problems on Ages Aptitude Problems and answers for all competitive exams preparation

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 Problems on Ages Impotent Formulas:

 1. Odd Days:
We are supposed to find the day of the week on a given date.
For this, we use the concept of 'odd days'.
In a given period, the number of days more than the complete weeks are called odd days.

2. Leap Year:
(i)  Every year divisible by 4 is a leap year, if it is not a century.
(ii) Every 4th century is a leap year and no other century is a leap year.
Note: A leap year has 366 days.

Examples:
Each of the years 1948, 2004, 1676 etc. is a leap year.
Each of the years 400, 800, 1200, 1600, 2000 etc. is a leap year.
None of the years 2001, 2002, 2003, 2005, 1800, 2100 is a leap year.

3. Ordinary Year:
The year which is not a leap year is called an ordinary years. An ordinary year has 365 days.

4. Counting of Odd Days:
(i) ordinary year = 365 days = (52 weeks + 1 day.)
    1 ordinary year has 1 odd day.
(ii). leap year = 366 days = (52 weeks + 2 days)
    1 leap year has 2 odd days.
(iii) 100 years = 76 ordinary years + 24 leap years
  = (76 x 1 + 24 x 2) odd days = 124 odd days.
  = (17 weeks + days)  5 odd days.
Number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2)  3 odd days.
Number of odd days in 300 years = (5 x 3)  1 odd day.
Number of odd days in 400 years = (5 x 4 + 1)  0 odd day.
Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.

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