1. A train 100 m long is running at the speed of 30 km/hr. Find the time taken by it to pass a man standing near the railway line.
A. 10 sec.
B. 12 sec.
C. 14 sec.
D. 16 sec.
= (25 / 3) m/sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100 /( 25 / 3)
= (100 x 3 / 25) sec
= 12 sec.
2. A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.
A. 52 kmph.
B. 62 kmph.
C. 72 kmph.
D. 80 kmph.
= (280/9 x 18/5)
= 112 kmph.
Speed of the train = (112 - 50)kmph
= 62 kmph.
3. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet ?
A. 9 a.m
B. 10 a.m
C. 10-30 a.m
D. 11 a.m
Distance covered by B in (x - 1) hours = 25 (x - 1) km
= 20x + 25 (x - I)
= 110
=> 45x = 135
x = 3.
So, they meet at 10 a.m
4. Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. The length of the faster train is
A. 80 m
B. 100 m
C. 120 m
D. 180 m
= (81 x 5/18) m/sec
= (45 / 2) m/sec
Length of the train = (45 / 2 x 8) m
= 180 m.
5. 30. A train 110 m long passes a man, running at 6 kmph in the direction opposite to that of the train, in 6 seconds The speed of the train is
A. 54 km/hr
B. 60 km/hr
C. 66 km/hr
D. 72 km/hr
= (110 / 6 x 18 /5) km/hr
= 66 km/hr
speed of the train be x kmph.
Relative Speed = (x + 6 ) kmph.
= x + 6
= 66
x = 60.
A. 10 sec.
B. 12 sec.
C. 14 sec.
D. 16 sec.
Explanation:
Speed of the train = (30 x 5/18)m/sec= (25 / 3) m/sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100 /( 25 / 3)
= (100 x 3 / 25) sec
= 12 sec.
2. A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.
A. 52 kmph.
B. 62 kmph.
C. 72 kmph.
D. 80 kmph.
Explanation:
Relative Speed = (280 / 9)m/sec= (280/9 x 18/5)
= 112 kmph.
Speed of the train = (112 - 50)kmph
= 62 kmph.
3. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet ?
A. 9 a.m
B. 10 a.m
C. 10-30 a.m
D. 11 a.m
Explanation:
Distance covered by A in x hours = 20 x kmDistance covered by B in (x - 1) hours = 25 (x - 1) km
= 20x + 25 (x - I)
= 110
=> 45x = 135
x = 3.
So, they meet at 10 a.m
4. Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. The length of the faster train is
A. 80 m
B. 100 m
C. 120 m
D. 180 m
Explanation:
Relative speed = (36 + 45) km/hr= (81 x 5/18) m/sec
= (45 / 2) m/sec
Length of the train = (45 / 2 x 8) m
= 180 m.
5. 30. A train 110 m long passes a man, running at 6 kmph in the direction opposite to that of the train, in 6 seconds The speed of the train is
A. 54 km/hr
B. 60 km/hr
C. 66 km/hr
D. 72 km/hr
Explanation:
Speed of the train relative to man = (110 / 6 ) m/sec= (110 / 6 x 18 /5) km/hr
= 66 km/hr
speed of the train be x kmph.
Relative Speed = (x + 6 ) kmph.
= x + 6
= 66
x = 60.
2 comments:
sir,
i am preparing SSC multi tasking for last 2 year i want to know more about the Problems on Trains Questions & Answers
pls help me for all exams and provide me all questions and ans about this.
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